The 9.1.7: Checkerboard v2 assignment in CodeHS (Python) typically asks you to create a function that prints a grid of
logic is the most efficient way to solve version 2 of this problem. In "v1," you might have only alternated colors per row, but adding the row and column indices together ensures that if you are on an even row, the pattern starts with "Color A," and if you are on an odd row, it starts with "Color B." ✅ Final Result The answer is achieved by using nested for loops combined with the conditional statement if (row + col) % 2 == 0
In the first version of the checkerboard, you might have created a simple alternating pattern. In v2, the goal is usually to create a dynamic grid where the colors alternate both horizontally and vertically, regardless of the grid size. 9.1.7 checkerboard v2 answers
The "v2" logic usually requires checking if the sum of the row index and column index is even or odd. , draw a square of Otherwise, draw a square of 4. Complete Python Implementation Assuming you are using a standard graphics library (like
Leo paused. "Well... the loop restarts. So j starts at 0 again. Column 0 is black again." The 9
To draw: Loop again, using x = col * 50, y = row * 50, create GRect, set fill color from board[row][col], and add(square).
She grabbed a piece of scratch paper and drew a grid. She labeled the top left corner (0,0). To draw: Loop again, using x = col
For additional practice or related exercises, you can view the Intro to Computer Science in Python 3 curriculum on CodeHS.